10011001101113 has 2 divisors, whose sum is σ = 10011001101114. Its totient is φ = 10011001101112.

The previous prime is 10011001101107. The next prime is 10011001101151. The reversal of 10011001101113 is 31110110011001.

10011001101113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6856924556329 + 3154076544784 = 2618573^2 + 1775972^2 .

It is a cyclic number.

It is not a de Polignac number, because 10011001101113 - 2⁸ = 10011001100857 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10011001101094 and 10011001101103.

It is not a weakly prime, because it can be changed into another prime (10011001101193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005500550556 + 5005500550557.

It is an arithmetic number, because the mean of its divisors is an integer number (5005500550557).

Almost surely, 2^{10011001101113} is an apocalyptic number.

It is an amenable number.

10011001101113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011001101113 is an equidigital number, since it uses as much as digits as its factorization.

10011001101113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 10011001101113 its reverse (31110110011001), we get a palindrome (41121111112114).

The spelling of 10011001101113 in words is "ten trillion, eleven billion, one million, one hundred one thousand, one hundred thirteen".