Base | Representation |
---|---|
bin | 10110110000110010110100… |
… | …010000101010011010111111 |
3 | 111010110102201112021212002111 |
4 | 112300302310100222122333 |
5 | 101110201012213031421 |
6 | 552525542151234451 |
7 | 30041501101543054 |
oct | 2660626420523277 |
9 | 433412645255074 |
10 | 100110122002111 |
11 | 29997512006281 |
12 | b28a019378a27 |
13 | 43b24619bb140 |
14 | 1aa14da2b302b |
15 | b89162465ee1 |
hex | 5b0cb442a6bf |
100110122002111 has 4 divisors (see below), whose sum is σ = 107810900617672. Its totient is φ = 92409343386552.
The previous prime is 100110122002103. The next prime is 100110122002133. The reversal of 100110122002111 is 111200221011001.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 100110122002111 - 23 = 100110122002103 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (13), and also a Moran number because the ratio is a prime number: 7700778615547 = 100110122002111 / (1 + 0 + 0 + 1 + 1 + 0 + 1 + 2 + 2 + 0 + 0 + 2 + 1 + 1 + 1).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 100110122002091 and 100110122002100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (100110122002141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3850389307761 + ... + 3850389307786.
It is an arithmetic number, because the mean of its divisors is an integer number (26952725154418).
Almost surely, 2100110122002111 is an apocalyptic number.
100110122002111 is a deficient number, since it is larger than the sum of its proper divisors (7700778615561).
100110122002111 is an equidigital number, since it uses as much as digits as its factorization.
100110122002111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7700778615560.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 100110122002111 its reverse (111200221011001), we get a palindrome (211310343013112).
The spelling of 100110122002111 in words is "one hundred trillion, one hundred ten billion, one hundred twenty-two million, two thousand, one hundred eleven".
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