Base | Representation |
---|---|
bin | 101110100111100000… |
… | …1111000001001001011 |
3 | 100120101211220000220012 |
4 | 1131033001320021023 |
5 | 3120011143434404 |
6 | 113553455422135 |
7 | 10142552102213 |
oct | 1351701701113 |
9 | 316354800805 |
10 | 100110139979 |
11 | 39502622983 |
12 | 1749a82494b |
13 | 9595593725 |
14 | 4bb9931243 |
15 | 290dc43a6e |
hex | 174f07824b |
100110139979 has 2 divisors, whose sum is σ = 100110139980. Its totient is φ = 100110139978.
The previous prime is 100110139933. The next prime is 100110140023. The reversal of 100110139979 is 979931011001.
It is a strong prime.
It is an emirp because it is prime and its reverse (979931011001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 100110139979 - 212 = 100110135883 is a prime.
It is a super-2 number, since 2×1001101399792 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (100110139079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055069989 + 50055069990.
It is an arithmetic number, because the mean of its divisors is an integer number (50055069990).
Almost surely, 2100110139979 is an apocalyptic number.
100110139979 is a deficient number, since it is larger than the sum of its proper divisors (1).
100110139979 is an equidigital number, since it uses as much as digits as its factorization.
100110139979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15309, while the sum is 41.
The spelling of 100110139979 in words is "one hundred billion, one hundred ten million, one hundred thirty-nine thousand, nine hundred seventy-nine".
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