Base | Representation |
---|---|
bin | 101110100111100001… |
… | …1000001111111000001 |
3 | 100120101212110101210012 |
4 | 1131033003001333001 |
5 | 3120011233124213 |
6 | 113553510114305 |
7 | 10142554502051 |
oct | 1351703017701 |
9 | 316355411705 |
10 | 100110442433 |
11 | 3950280a141 |
12 | 1749a94b995 |
13 | 959566b2b1 |
14 | 4bb99ad561 |
15 | 290dca34a8 |
hex | 174f0c1fc1 |
100110442433 has 2 divisors, whose sum is σ = 100110442434. Its totient is φ = 100110442432.
The previous prime is 100110442417. The next prime is 100110442501. The reversal of 100110442433 is 334244011001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 83646473089 + 16463969344 = 289217^2 + 128312^2 .
It is a cyclic number.
It is not a de Polignac number, because 100110442433 - 24 = 100110442417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100110442399 and 100110442408.
It is not a weakly prime, because it can be changed into another prime (100110442933) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055221216 + 50055221217.
It is an arithmetic number, because the mean of its divisors is an integer number (50055221217).
Almost surely, 2100110442433 is an apocalyptic number.
It is an amenable number.
100110442433 is a deficient number, since it is larger than the sum of its proper divisors (1).
100110442433 is an equidigital number, since it uses as much as digits as its factorization.
100110442433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 100110442433 its reverse (334244011001), we get a palindrome (434354453434).
The spelling of 100110442433 in words is "one hundred billion, one hundred ten million, four hundred forty-two thousand, four hundred thirty-three".
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