Base | Representation |
---|---|
bin | 1001000110101110010000… |
… | …0011110101101100101011 |
3 | 1022110001101202212020210021 |
4 | 2101223210003311230223 |
5 | 2303010213100330212 |
6 | 33143011424501311 |
7 | 2052164251030303 |
oct | 221534403655453 |
9 | 38401352766707 |
10 | 10011100011307 |
11 | 320a757a7088a |
12 | 115827517a837 |
13 | 5780729cb855 |
14 | 26877b3d4603 |
15 | 12562968a307 |
hex | 91ae40f5b2b |
10011100011307 has 2 divisors, whose sum is σ = 10011100011308. Its totient is φ = 10011100011306.
The previous prime is 10011100011301. The next prime is 10011100011317. The reversal of 10011100011307 is 70311000111001.
10011100011307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10011100011307 - 23 = 10011100011299 is a prime.
It is not a weakly prime, because it can be changed into another prime (10011100011301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005550005653 + 5005550005654.
It is an arithmetic number, because the mean of its divisors is an integer number (5005550005654).
Almost surely, 210011100011307 is an apocalyptic number.
10011100011307 is a deficient number, since it is larger than the sum of its proper divisors (1).
10011100011307 is an equidigital number, since it uses as much as digits as its factorization.
10011100011307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21, while the sum is 16.
Adding to 10011100011307 its reverse (70311000111001), we get a palindrome (80322100122308).
The spelling of 10011100011307 in words is "ten trillion, eleven billion, one hundred million, eleven thousand, three hundred seven".
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