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100111010000153 is a prime number
BaseRepresentation
bin10110110000110011101001…
…001100000110110100011001
3111010110112000102012211101212
4112300303221030012310121
5101110204322030001103
6552530210232152505
730041532103443455
oct2660635114066431
9433415012184355
10100111010000153
1129997928290359
12b28a226838735
1343b2573971979
141aa15821c7665
15b891b53c17d8
hex5b0ce9306d19

100111010000153 has 2 divisors, whose sum is σ = 100111010000154. Its totient is φ = 100111010000152.

The previous prime is 100111010000093. The next prime is 100111010000159. The reversal of 100111010000153 is 351000010111001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99279143787664 + 831866212489 = 9963892^2 + 912067^2 .

It is a cyclic number.

It is not a de Polignac number, because 100111010000153 - 234 = 100093830130969 is a prime.

It is not a weakly prime, because it can be changed into another prime (100111010000159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055505000076 + 50055505000077.

It is an arithmetic number, because the mean of its divisors is an integer number (50055505000077).

Almost surely, 2100111010000153 is an apocalyptic number.

It is an amenable number.

100111010000153 is a deficient number, since it is larger than the sum of its proper divisors (1).

100111010000153 is an equidigital number, since it uses as much as digits as its factorization.

100111010000153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 14.

Adding to 100111010000153 its reverse (351000010111001), we get a palindrome (451111020111154).

The spelling of 100111010000153 in words is "one hundred trillion, one hundred eleven billion, ten million, one hundred fifty-three", and thus it is an aban number.