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100111012133 = 119101001103
BaseRepresentation
bin101110100111100010…
…1001101000100100101
3100120101220112100021012
41131033011031010211
53120011404342013
6113553530232005
710142562364016
oct1351705150445
9316356470235
10100111012133
1139503069170
121749ab85605
13959580a6b2
144bb9abb00d
15290dd671a8
hex174f14d125

100111012133 has 4 divisors (see below), whose sum is σ = 109212013248. Its totient is φ = 91010011020.

The previous prime is 100111012121. The next prime is 100111012171. The reversal of 100111012133 is 331210111001.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100111012133 - 210 = 100111011109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100111015133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4550500541 + ... + 4550500562.

It is an arithmetic number, because the mean of its divisors is an integer number (27303003312).

Almost surely, 2100111012133 is an apocalyptic number.

It is an amenable number.

100111012133 is a deficient number, since it is larger than the sum of its proper divisors (9101001115).

100111012133 is an equidigital number, since it uses as much as digits as its factorization.

100111012133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9101001114.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 100111012133 its reverse (331210111001), we get a palindrome (431321123134).

The spelling of 100111012133 in words is "one hundred billion, one hundred eleven million, twelve thousand, one hundred thirty-three".

Divisors: 1 11 9101001103 100111012133