10011112011833 has 2 divisors, whose sum is σ = 10011112011834. Its totient is φ = 10011112011832.

The previous prime is 10011112011827. The next prime is 10011112011847. The reversal of 10011112011833 is 33811021111001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9481983794089 + 529128217744 = 3079283^2 + 727412^2 .

It is a cyclic number.

It is not a de Polignac number, because 10011112011833 - 2²⁰ = 10011110963257 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10011112011799 and 10011112011808.

It is not a weakly prime, because it can be changed into another prime (10011112011133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005556005916 + 5005556005917.

It is an arithmetic number, because the mean of its divisors is an integer number (5005556005917).

Almost surely, 2^{10011112011833} is an apocalyptic number.

It is an amenable number.

10011112011833 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011112011833 is an equidigital number, since it uses as much as digits as its factorization.

10011112011833 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 23.

Adding to 10011112011833 its reverse (33811021111001), we get a palindrome (43822133122834).

The spelling of 10011112011833 in words is "ten trillion, eleven billion, one hundred twelve million, eleven thousand, eight hundred thirty-three".