Base | Representation |
---|---|
bin | 10110110000110011110100… |
… | …100000111001111111100001 |
3 | 111010110112111122201220221221 |
4 | 112300303310200321333201 |
5 | 101110210214200031032 |
6 | 552530241140415041 |
7 | 30041536601436661 |
oct | 2660636440717741 |
9 | 433415448656857 |
10 | 100111200002017 |
11 | 29997a15564596 |
12 | b28a27a3a7481 |
13 | 43b25a41381c9 |
14 | 1aa159d5261a1 |
15 | b891c6e03597 |
hex | 5b0cf4839fe1 |
100111200002017 has 2 divisors, whose sum is σ = 100111200002018. Its totient is φ = 100111200002016.
The previous prime is 100111200001921. The next prime is 100111200002041. The reversal of 100111200002017 is 710200002111001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 95223169831696 + 4888030170321 = 9758236^2 + 2210889^2 .
It is a cyclic number.
It is not a de Polignac number, because 100111200002017 - 223 = 100111191613409 is a prime.
It is not a weakly prime, because it can be changed into another prime (100111200092017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055600001008 + 50055600001009.
It is an arithmetic number, because the mean of its divisors is an integer number (50055600001009).
Almost surely, 2100111200002017 is an apocalyptic number.
It is an amenable number.
100111200002017 is a deficient number, since it is larger than the sum of its proper divisors (1).
100111200002017 is an equidigital number, since it uses as much as digits as its factorization.
100111200002017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28, while the sum is 16.
Adding to 100111200002017 its reverse (710200002111001), we get a palindrome (810311202113018).
The spelling of 100111200002017 in words is "one hundred trillion, one hundred eleven billion, two hundred million, two thousand, seventeen".
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