10011134333131 has 4 divisors (see below), whose sum is σ = 10035611434600. Its totient is φ = 9986657231664.

The previous prime is 10011134333129. The next prime is 10011134333183. The reversal of 10011134333131 is 13133343111001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10011134333131 - 2¹ = 10011134333129 is a prime.

It is a super-2 number, since 2×10011134333131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10011134333096 and 10011134333105.

It is not an unprimeable number, because it can be changed into a prime (10011134333531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12238550121 + ... + 12238550938.

It is an arithmetic number, because the mean of its divisors is an integer number (2508902858650).

Almost surely, 2^{10011134333131} is an apocalyptic number.

10011134333131 is a deficient number, since it is larger than the sum of its proper divisors (24477101469).

10011134333131 is an equidigital number, since it uses as much as digits as its factorization.

10011134333131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24477101468.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 10011134333131 its reverse (13133343111001), we get a palindrome (23144477444132).

The spelling of 10011134333131 in words is "ten trillion, eleven billion, one hundred thirty-four million, three hundred thirty-three thousand, one hundred thirty-one".