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10011151454113 is a prime number
BaseRepresentation
bin1001000110101110011100…
…1000000100111110100001
31022110001112100122211001101
42101223213020010332201
52303010314233012423
633143020503234401
72052165444214315
oct221534710047641
938401470584041
1010011151454113
11320a7840075a7
12115828a448a01
13578080570894
14268784185b45
1512562de4c7ad
hex91ae7204fa1

10011151454113 has 2 divisors, whose sum is σ = 10011151454114. Its totient is φ = 10011151454112.

The previous prime is 10011151454093. The next prime is 10011151454123. The reversal of 10011151454113 is 31145415111001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10006542809344 + 4608644769 = 3163312^2 + 67887^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10011151454113 is a prime.

It is not a weakly prime, because it can be changed into another prime (10011151454123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005575727056 + 5005575727057.

It is an arithmetic number, because the mean of its divisors is an integer number (5005575727057).

Almost surely, 210011151454113 is an apocalyptic number.

It is an amenable number.

10011151454113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011151454113 is an equidigital number, since it uses as much as digits as its factorization.

10011151454113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 28.

Adding to 10011151454113 its reverse (31145415111001), we get a palindrome (41156566565114).

The spelling of 10011151454113 in words is "ten trillion, eleven billion, one hundred fifty-one million, four hundred fifty-four thousand, one hundred thirteen".