100112010110113 has 2 divisors, whose sum is σ = 100112010110114. Its totient is φ = 100112010110112.

The previous prime is 100112010110083. The next prime is 100112010110117. The reversal of 100112010110113 is 311011010211001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99950966012304 + 161044097809 = 9997548^2 + 401303^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100112010110113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100112010110093 and 100112010110102.

It is not a weakly prime, because it can be changed into another prime (100112010110117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50056005055056 + 50056005055057.

It is an arithmetic number, because the mean of its divisors is an integer number (50056005055057).

Almost surely, 2^{100112010110113} is an apocalyptic number.

It is an amenable number.

100112010110113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100112010110113 is an equidigital number, since it uses as much as digits as its factorization.

100112010110113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 100112010110113 its reverse (311011010211001), we get a palindrome (411123020321114).

The spelling of 100112010110113 in words is "one hundred trillion, one hundred twelve billion, ten million, one hundred ten thousand, one hundred thirteen".