Base | Representation |
---|---|
bin | 10110110000110100100100… |
… | …110111000101000111101011 |
3 | 111010110121121012000001012121 |
4 | 112300310210313011013223 |
5 | 101110213344321334011 |
6 | 552530453433452111 |
7 | 30041565651023512 |
oct | 2660644467050753 |
9 | 433417535001177 |
10 | 100112011121131 |
11 | 299982a13aa369 |
12 | b28a465b71037 |
13 | 43b26a31b2149 |
14 | 1aa1639147679 |
15 | b89223224e71 |
hex | 5b0d24dc51eb |
100112011121131 has 2 divisors, whose sum is σ = 100112011121132. Its totient is φ = 100112011121130.
The previous prime is 100112011121047. The next prime is 100112011121153. The reversal of 100112011121131 is 131121110211001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100112011121131 - 221 = 100112009023979 is a prime.
It is a super-2 number, since 2×1001120111211312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (100112011121191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50056005560565 + 50056005560566.
It is an arithmetic number, because the mean of its divisors is an integer number (50056005560566).
Almost surely, 2100112011121131 is an apocalyptic number.
100112011121131 is a deficient number, since it is larger than the sum of its proper divisors (1).
100112011121131 is an equidigital number, since it uses as much as digits as its factorization.
100112011121131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 16.
Adding to 100112011121131 its reverse (131121110211001), we get a palindrome (231233121332132).
The spelling of 100112011121131 in words is "one hundred trillion, one hundred twelve billion, eleven million, one hundred twenty-one thousand, one hundred thirty-one".
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