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100112020211051 is a prime number
BaseRepresentation
bin10110110000110100100101…
…011001110000010101101011
3111010110121121211002212020022
4112300310211121300111223
5101110213404133223201
6552530454400351055
730041566121212652
oct2660644531602553
9433417554085208
10100112020211051
11299982a65487a2
12b28a46901548b
1343b26a50456b4
141aa163a432199
15b89223e1d41b
hex5b0d2567056b

100112020211051 has 2 divisors, whose sum is σ = 100112020211052. Its totient is φ = 100112020211050.

The previous prime is 100112020210991. The next prime is 100112020211057. The reversal of 100112020211051 is 150112020211001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 100112020211051 - 218 = 100112019948907 is a prime.

It is not a weakly prime, because it can be changed into another prime (100112020211057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50056010105525 + 50056010105526.

It is an arithmetic number, because the mean of its divisors is an integer number (50056010105526).

Almost surely, 2100112020211051 is an apocalyptic number.

100112020211051 is a deficient number, since it is larger than the sum of its proper divisors (1).

100112020211051 is an equidigital number, since it uses as much as digits as its factorization.

100112020211051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40, while the sum is 17.

Adding to 100112020211051 its reverse (150112020211001), we get a palindrome (250224040422052).

The spelling of 100112020211051 in words is "one hundred trillion, one hundred twelve billion, twenty million, two hundred eleven thousand, fifty-one".