Base | Representation |
---|---|
bin | 10110110000110100101011… |
… | …011010101101011000110011 |
3 | 111010110121212211222210022212 |
4 | 112300310223122231120303 |
5 | 101110214111001440103 |
6 | 552530512403322335 |
7 | 30041601455030663 |
oct | 2660645332553063 |
9 | 433417784883285 |
10 | 100112121124403 |
11 | 29998348503463 |
12 | b28a4969803ab |
13 | 43b26bcc18b3b |
14 | 1aa16499c01a3 |
15 | b8922cc037d8 |
hex | 5b0d2b6ad633 |
100112121124403 has 2 divisors, whose sum is σ = 100112121124404. Its totient is φ = 100112121124402.
The previous prime is 100112121124391. The next prime is 100112121124427. The reversal of 100112121124403 is 304421121211001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100112121124403 - 212 = 100112121120307 is a prime.
It is not a weakly prime, because it can be changed into another prime (100112121124003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50056060562201 + 50056060562202.
It is an arithmetic number, because the mean of its divisors is an integer number (50056060562202).
Almost surely, 2100112121124403 is an apocalyptic number.
100112121124403 is a deficient number, since it is larger than the sum of its proper divisors (1).
100112121124403 is an equidigital number, since it uses as much as digits as its factorization.
100112121124403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 100112121124403 its reverse (304421121211001), we get a palindrome (404533242335404).
The spelling of 100112121124403 in words is "one hundred trillion, one hundred twelve billion, one hundred twenty-one million, one hundred twenty-four thousand, four hundred three".
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