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10011222400433 is a prime number
BaseRepresentation
bin1001000110101110101101…
…0110101101110110110001
31022110001201022011021002212
42101223223112231312301
52303010440413303213
633143031520021505
72052200265232022
oct221535326556661
938401638137085
1010011222400433
11320a810064621
1211582aa161895
13578092181057
1426878d772c49
151256352b39a8
hex91aeb5addb1

10011222400433 has 2 divisors, whose sum is σ = 10011222400434. Its totient is φ = 10011222400432.

The previous prime is 10011222400409. The next prime is 10011222400477. The reversal of 10011222400433 is 33400422211001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9524432924224 + 486789476209 = 3086168^2 + 697703^2 .

It is a cyclic number.

It is not a de Polignac number, because 10011222400433 - 214 = 10011222384049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10011222400399 and 10011222400408.

It is not a weakly prime, because it can be changed into another prime (10011222400483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005611200216 + 5005611200217.

It is an arithmetic number, because the mean of its divisors is an integer number (5005611200217).

Almost surely, 210011222400433 is an apocalyptic number.

It is an amenable number.

10011222400433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011222400433 is an equidigital number, since it uses as much as digits as its factorization.

10011222400433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 10011222400433 its reverse (33400422211001), we get a palindrome (43411644611434).

The spelling of 10011222400433 in words is "ten trillion, eleven billion, two hundred twenty-two million, four hundred thousand, four hundred thirty-three".