Base | Representation |
---|---|
bin | 101110100111100100… |
… | …1111011101010001011 |
3 | 100120101222212022101211 |
4 | 1131033021323222023 |
5 | 3120012214022111 |
6 | 113554012553551 |
7 | 10142606045305 |
oct | 1351711735213 |
9 | 316358768354 |
10 | 100112251531 |
11 | 39503835366 |
12 | 1749b4828b7 |
13 | 9595b52876 |
14 | 4bb9d20975 |
15 | 290e00e521 |
hex | 174f27ba8b |
100112251531 has 2 divisors, whose sum is σ = 100112251532. Its totient is φ = 100112251530.
The previous prime is 100112251513. The next prime is 100112251607. The reversal of 100112251531 is 135152211001.
Together with previous prime (100112251513) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100112251531 - 27 = 100112251403 is a prime.
It is a super-2 number, since 2×1001122515312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (100112251331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50056125765 + 50056125766.
It is an arithmetic number, because the mean of its divisors is an integer number (50056125766).
Almost surely, 2100112251531 is an apocalyptic number.
100112251531 is a deficient number, since it is larger than the sum of its proper divisors (1).
100112251531 is an equidigital number, since it uses as much as digits as its factorization.
100112251531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 300, while the sum is 22.
Adding to 100112251531 its reverse (135152211001), we get a palindrome (235264462532).
The spelling of 100112251531 in words is "one hundred billion, one hundred twelve million, two hundred fifty-one thousand, five hundred thirty-one".
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