100113021311100 has 288 divisors, whose sum is σ = 337825502784000. Its totient is φ = 22880999232000.

The previous prime is 100113021311077. The next prime is 100113021311123. The reversal of 100113021311100 is 1113120311001.

It is an interprime number because it is at equal distance from previous prime (100113021311077) and next prime (100113021311123).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 100113021311100.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1426056000 + ... + 1426126200.

It is an arithmetic number, because the mean of its divisors is an integer number (1173005218000).

Almost surely, 2^{100113021311100} is an apocalyptic number.

100113021311100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 100113021311100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (168912751392000).

100113021311100 is an abundant number, since it is smaller than the sum of its proper divisors (237712481472900).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

100113021311100 is a wasteful number, since it uses less digits than its factorization.

100113021311100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 84098 (or 84077 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 100113021311100 its reverse (1113120311001), we get a palindrome (101226141622101).

The spelling of 100113021311100 in words is "one hundred trillion, one hundred thirteen billion, twenty-one million, three hundred eleven thousand, one hundred".