Base | Representation |
---|---|
bin | 11101001000110000001… |
… | …00011111101000111011 |
3 | 10112201002112222220200201 |
4 | 32210120010133220323 |
5 | 112400304042230243 |
6 | 2043525140143031 |
7 | 132220651614145 |
oct | 16443004375073 |
9 | 3481075886621 |
10 | 1001131211323 |
11 | 356639518791 |
12 | 142038997a77 |
13 | 73538756959 |
14 | 3665278bc95 |
15 | 1b095c1504d |
hex | e91811fa3b |
1001131211323 has 2 divisors, whose sum is σ = 1001131211324. Its totient is φ = 1001131211322.
The previous prime is 1001131211317. The next prime is 1001131211347. The reversal of 1001131211323 is 3231121311001.
1001131211323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1001131211323 - 237 = 863692257851 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1001131211323.
It is not a weakly prime, because it can be changed into another prime (1001131211383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500565605661 + 500565605662.
It is an arithmetic number, because the mean of its divisors is an integer number (500565605662).
Almost surely, 21001131211323 is an apocalyptic number.
1001131211323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001131211323 is an equidigital number, since it uses as much as digits as its factorization.
1001131211323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 1001131211323 its reverse (3231121311001), we get a palindrome (4232252522324).
The spelling of 1001131211323 in words is "one trillion, one billion, one hundred thirty-one million, two hundred eleven thousand, three hundred twenty-three".
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