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10011313103 = 11910119373
BaseRepresentation
bin10010101001011100…
…01000001111001111
3221211201001101210012
421110232020033033
5131000344004403
64333225103435
7503042520521
oct112456101717
927751041705
1010011313103
114278141790
121b34927b7b
13c3714b90c
146ad869a11
153d8d94ed8
hex254b883cf

10011313103 has 4 divisors (see below), whose sum is σ = 10921432488. Its totient is φ = 9101193720.

The previous prime is 10011313093. The next prime is 10011313183. The reversal of 10011313103 is 30131311001.

It is a happy number.

10011313103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10011313103 - 220 = 10010264527 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10011313183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 455059676 + ... + 455059697.

It is an arithmetic number, because the mean of its divisors is an integer number (2730358122).

Almost surely, 210011313103 is an apocalyptic number.

10011313103 is a deficient number, since it is larger than the sum of its proper divisors (910119385).

10011313103 is an equidigital number, since it uses as much as digits as its factorization.

10011313103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 910119384.

The product of its (nonzero) digits is 27, while the sum is 14.

Adding to 10011313103 its reverse (30131311001), we get a palindrome (40142624104).

The spelling of 10011313103 in words is "ten billion, eleven million, three hundred thirteen thousand, one hundred three".

Divisors: 1 11 910119373 10011313103