Base | Representation |
---|---|
bin | 10110110000110101101011… |
… | …110010111010001001100001 |
3 | 111010110201200010100211011101 |
4 | 112300311223302322021201 |
5 | 101110223314002204303 |
6 | 552531211505314401 |
7 | 30041640311432311 |
oct | 2660655362721141 |
9 | 433421603324141 |
10 | 100113201209953 |
11 | 29998852156748 |
12 | b28a738635a01 |
13 | 43b2832916309 |
14 | 1aa170d217441 |
15 | b89292953d1d |
hex | 5b0d6bcba261 |
100113201209953 has 2 divisors, whose sum is σ = 100113201209954. Its totient is φ = 100113201209952.
The previous prime is 100113201209891. The next prime is 100113201210017. The reversal of 100113201209953 is 359902102311001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 98896819417344 + 1216381792609 = 9944688^2 + 1102897^2 .
It is a cyclic number.
It is not a de Polignac number, because 100113201209953 - 225 = 100113167655521 is a prime.
It is not a weakly prime, because it can be changed into another prime (100113201209353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50056600604976 + 50056600604977.
It is an arithmetic number, because the mean of its divisors is an integer number (50056600604977).
Almost surely, 2100113201209953 is an apocalyptic number.
It is an amenable number.
100113201209953 is a deficient number, since it is larger than the sum of its proper divisors (1).
100113201209953 is an equidigital number, since it uses as much as digits as its factorization.
100113201209953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14580, while the sum is 37.
The spelling of 100113201209953 in words is "one hundred trillion, one hundred thirteen billion, two hundred one million, two hundred nine thousand, nine hundred fifty-three".
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