Base | Representation |
---|---|
bin | 1001000110110001010110… |
… | …1101011010011101000011 |
3 | 1022110010112211021010022221 |
4 | 2101230111231122131003 |
5 | 2303013414321241342 |
6 | 33143230222311511 |
7 | 2052224014202335 |
oct | 221542555323503 |
9 | 38403484233287 |
10 | 10011932993347 |
11 | 321004518959a |
12 | 1158468128597 |
13 | 57817645bb2c |
14 | 268819ca7455 |
15 | 125677879a67 |
hex | 91b15b5a743 |
10011932993347 has 2 divisors, whose sum is σ = 10011932993348. Its totient is φ = 10011932993346.
The previous prime is 10011932993341. The next prime is 10011932993393. The reversal of 10011932993347 is 74339923911001.
10011932993347 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10011932993347 - 211 = 10011932991299 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10011932993294 and 10011932993303.
It is not a weakly prime, because it can be changed into another prime (10011932993341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005966496673 + 5005966496674.
It is an arithmetic number, because the mean of its divisors is an integer number (5005966496674).
Almost surely, 210011932993347 is an apocalyptic number.
10011932993347 is a deficient number, since it is larger than the sum of its proper divisors (1).
10011932993347 is an equidigital number, since it uses as much as digits as its factorization.
10011932993347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1102248, while the sum is 52.
The spelling of 10011932993347 in words is "ten trillion, eleven billion, nine hundred thirty-two million, nine hundred ninety-three thousand, three hundred forty-seven".
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