1001201120023 has 4 divisors (see below), whose sum is σ = 1078216590808. Its totient is φ = 924185649240.

The previous prime is 1001201120009. The next prime is 1001201120057. The reversal of 1001201120023 is 3200211021001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1001201120023 - 2²⁹ = 1000664249111 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (13), and also a Moran number because the ratio is a prime number: 77015470771 = 1001201120023 / (1 + 0 + 0 + 1 + 2 + 0 + 1 + 1 + 2 + 0 + 0 + 2 + 3).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1001201119985 and 1001201120012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1001201120083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38507735373 + ... + 38507735398.

It is an arithmetic number, because the mean of its divisors is an integer number (269554147702).

Almost surely, 2^{1001201120023} is an apocalyptic number.

1001201120023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1001201120023 is a deficient number, since it is larger than the sum of its proper divisors (77015470785).

1001201120023 is an equidigital number, since it uses as much as digits as its factorization.

1001201120023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 77015470784.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 1001201120023 its reverse (3200211021001), we get a palindrome (4201412141024).

The spelling of 1001201120023 in words is "one trillion, one billion, two hundred one million, one hundred twenty thousand, twenty-three".