Base | Representation |
---|---|
bin | 10110110000111100001110… |
… | …001001100011010100000101 |
3 | 111010111101210021111102020220 |
4 | 112300330032021203110011 |
5 | 101110332202311201041 |
6 | 552534332155014553 |
7 | 30042306246362253 |
oct | 2660741611432405 |
9 | 433441707442226 |
10 | 100120220022021 |
11 | 299a082408a081 |
12 | b28bb7713a459 |
13 | 43b33b0aa7a54 |
14 | 1aa1bb746d5d3 |
15 | b89553c36d66 |
hex | 5b0f0e263505 |
100120220022021 has 8 divisors (see below), whose sum is σ = 133496978692704. Its totient is φ = 66745137349680.
The previous prime is 100120220021977. The next prime is 100120220022037. The reversal of 100120220022021 is 120220022021001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 100120220022021 - 213 = 100120220013829 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (100120220022041) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 418860190 + ... + 419099151.
It is an arithmetic number, because the mean of its divisors is an integer number (16687122336588).
Almost surely, 2100120220022021 is an apocalyptic number.
It is an amenable number.
100120220022021 is a deficient number, since it is larger than the sum of its proper divisors (33376758670683).
100120220022021 is an equidigital number, since it uses as much as digits as its factorization.
100120220022021 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 837999171.
The product of its (nonzero) digits is 64, while the sum is 15.
Adding to 100120220022021 its reverse (120220022021001), we get a palindrome (220340242043022).
The spelling of 100120220022021 in words is "one hundred trillion, one hundred twenty billion, two hundred twenty million, twenty-two thousand, twenty-one".
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