Base | Representation |
---|---|
bin | 10110110000111101000011… |
… | …010001100011011101001011 |
3 | 111010111111002101121122112101 |
4 | 112300331003101203131023 |
5 | 101110341013443442303 |
6 | 552535000434254231 |
7 | 30042340321254022 |
oct | 2660750321433513 |
9 | 433444071548471 |
10 | 100121111312203 |
11 | 299a1141202633 |
12 | b290185727377 |
13 | 43b34c3641ba7 |
14 | 1aa1c5d99d8b9 |
15 | b895a70e2d1d |
hex | 5b0f4346374b |
100121111312203 has 2 divisors, whose sum is σ = 100121111312204. Its totient is φ = 100121111312202.
The previous prime is 100121111312197. The next prime is 100121111312219. The reversal of 100121111312203 is 302213111121001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100121111312203 - 29 = 100121111311691 is a prime.
It is not a weakly prime, because it can be changed into another prime (100121111313203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060555656101 + 50060555656102.
It is an arithmetic number, because the mean of its divisors is an integer number (50060555656102).
Almost surely, 2100121111312203 is an apocalyptic number.
100121111312203 is a deficient number, since it is larger than the sum of its proper divisors (1).
100121111312203 is an equidigital number, since it uses as much as digits as its factorization.
100121111312203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 100121111312203 its reverse (302213111121001), we get a palindrome (402334222433204).
The spelling of 100121111312203 in words is "one hundred trillion, one hundred twenty-one billion, one hundred eleven million, three hundred twelve thousand, two hundred three".
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