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1001211213011 is a prime number
BaseRepresentation
bin11101001000111001101…
…01101011010011010011
310112201022010112102101012
432210130311223103103
5112400440032304021
62043541115001135
7132222642615212
oct16443465532323
93481263472335
101001211213011
1135667a6a0189
1214205b7391ab
137354c1b7a29
143665d255079
151b09cc6935b
hexe91cd6b4d3

1001211213011 has 2 divisors, whose sum is σ = 1001211213012. Its totient is φ = 1001211213010.

The previous prime is 1001211212983. The next prime is 1001211213049. The reversal of 1001211213011 is 1103121121001.

It is a weak prime.

It is an emirp because it is prime and its reverse (1103121121001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1001211213011 is a prime.

It is a super-2 number, since 2×10012112130112 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1001211213091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500605606505 + 500605606506.

It is an arithmetic number, because the mean of its divisors is an integer number (500605606506).

Almost surely, 21001211213011 is an apocalyptic number.

1001211213011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001211213011 is an equidigital number, since it uses as much as digits as its factorization.

1001211213011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 1001211213011 its reverse (1103121121001), we get a palindrome (2104332334012).

The spelling of 1001211213011 in words is "one trillion, one billion, two hundred eleven million, two hundred thirteen thousand, eleven".