Base | Representation |
---|---|
bin | 1001000110110010000001… |
… | …1100111011000110100011 |
3 | 1022110011000101101120211021 |
4 | 2101230200130323012203 |
5 | 2303014301441020003 |
6 | 33143300141230311 |
7 | 2052231333123436 |
oct | 221544034730643 |
9 | 38404011346737 |
10 | 10012113220003 |
11 | 3210127996544 |
12 | 11584b8562397 |
13 | 5781a48b1c1b |
14 | 268835bbd81d |
15 | 1256885ca2bd |
hex | 91b2073b1a3 |
10012113220003 has 2 divisors, whose sum is σ = 10012113220004. Its totient is φ = 10012113220002.
The previous prime is 10012113219971. The next prime is 10012113220009. The reversal of 10012113220003 is 30002231121001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10012113220003 - 25 = 10012113219971 is a prime.
It is a super-2 number, since 2×100121132200032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10012113220009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006056610001 + 5006056610002.
It is an arithmetic number, because the mean of its divisors is an integer number (5006056610002).
Almost surely, 210012113220003 is an apocalyptic number.
10012113220003 is a deficient number, since it is larger than the sum of its proper divisors (1).
10012113220003 is an equidigital number, since it uses as much as digits as its factorization.
10012113220003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 10012113220003 its reverse (30002231121001), we get a palindrome (40014344341004).
The spelling of 10012113220003 in words is "ten trillion, twelve billion, one hundred thirteen million, two hundred twenty thousand, three".
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