Base | Representation |
---|---|
bin | 10110110000111101001001… |
… | …001110100110001000110011 |
3 | 111010111111100100120110220022 |
4 | 112300331021032212020303 |
5 | 101110341220031400201 |
6 | 552535014403234055 |
7 | 30042342643301156 |
oct | 2660751116461063 |
9 | 433444310513808 |
10 | 100121211200051 |
11 | 299a1192627878 |
12 | b2901b307892b |
13 | 43b350b246622 |
14 | 1aa1c6cd61c9d |
15 | b895b0c7441b |
hex | 5b0f493a6233 |
100121211200051 has 2 divisors, whose sum is σ = 100121211200052. Its totient is φ = 100121211200050.
The previous prime is 100121211200033. The next prime is 100121211200113. The reversal of 100121211200051 is 150002112121001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100121211200051 - 238 = 99846333293107 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (100121211200011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060605600025 + 50060605600026.
It is an arithmetic number, because the mean of its divisors is an integer number (50060605600026).
Almost surely, 2100121211200051 is an apocalyptic number.
100121211200051 is a deficient number, since it is larger than the sum of its proper divisors (1).
100121211200051 is an equidigital number, since it uses as much as digits as its factorization.
100121211200051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 100121211200051 its reverse (150002112121001), we get a palindrome (250123323321052).
The spelling of 100121211200051 in words is "one hundred trillion, one hundred twenty-one billion, two hundred eleven million, two hundred thousand, fifty-one".
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