1001214141 has 4 divisors (see below), whose sum is σ = 1334952192. Its totient is φ = 667476092.

The previous prime is 1001214121. The next prime is 1001214157. The reversal of 1001214141 is 1414121001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1414121001 = 3 ⋅471373667.

It is a cyclic number.

It is not a de Polignac number, because 1001214141 - 2⁶ = 1001214077 is a prime.

It is a super-2 number, since 2×1001214141² = 2004859512276735762, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1001214141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1001214121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166869021 + ... + 166869026.

It is an arithmetic number, because the mean of its divisors is an integer number (333738048).

Almost surely, 2^1001214141 is an apocalyptic number.

It is an amenable number.

1001214141 is a deficient number, since it is larger than the sum of its proper divisors (333738051).

1001214141 is an equidigital number, since it uses as much as digits as its factorization.

1001214141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 333738050.

The product of its (nonzero) digits is 32, while the sum is 15.

The square root of 1001214141 is about 31641.9680329780. The cubic root of 1001214141 is about 1000.4045499839.

Subtracting from 1001214141 its sum of digits (15), we obtain a triangular number (1001214126 = T₄₄₇₄₈).

Adding to 1001214141 its reverse (1414121001), we get a palindrome (2415335142).

The spelling of 1001214141 in words is "one billion, one million, two hundred fourteen thousand, one hundred forty-one".