100122100213 has 4 divisors (see below), whose sum is σ = 100172088288. Its totient is φ = 100072112140.

The previous prime is 100122100097. The next prime is 100122100217. The reversal of 100122100213 is 312001221001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100122100213 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100122100193 and 100122100202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100122100217) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24991033 + ... + 24995038.

It is an arithmetic number, because the mean of its divisors is an integer number (25043022072).

Almost surely, 2^100122100213 is an apocalyptic number.

It is an amenable number.

100122100213 is a deficient number, since it is larger than the sum of its proper divisors (49988075).

100122100213 is an equidigital number, since it uses as much as digits as its factorization.

100122100213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49988074.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 100122100213 its reverse (312001221001), we get a palindrome (412123321214).

The spelling of 100122100213 in words is "one hundred billion, one hundred twenty-two million, one hundred thousand, two hundred thirteen".