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100122310020121 is a prime number
BaseRepresentation
bin10110110000111110001010…
…101110010000110000011001
3111010111121011221012022122221
4112300332022232100300121
5101110400442331120441
6552535315414544041
730042412115151214
oct2660761256206031
9433447157168587
10100122310020121
11299a16a6906634
12b29045b068021
1343b3654aa320c
141aa1d34c7477b
15b896274758d1
hex5b0f8ab90c19

100122310020121 has 2 divisors, whose sum is σ = 100122310020122. Its totient is φ = 100122310020120.

The previous prime is 100122310020059. The next prime is 100122310020143. The reversal of 100122310020121 is 121020013221001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68627373178896 + 31494936841225 = 8284164^2 + 5612035^2 .

It is a cyclic number.

It is not a de Polignac number, because 100122310020121 - 225 = 100122276465689 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100122310020095 and 100122310020104.

It is not a weakly prime, because it can be changed into another prime (100122310000121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50061155010060 + 50061155010061.

It is an arithmetic number, because the mean of its divisors is an integer number (50061155010061).

Almost surely, 2100122310020121 is an apocalyptic number.

It is an amenable number.

100122310020121 is a deficient number, since it is larger than the sum of its proper divisors (1).

100122310020121 is an equidigital number, since it uses as much as digits as its factorization.

100122310020121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 100122310020121 its reverse (121020013221001), we get a palindrome (221142323241122).

The spelling of 100122310020121 in words is "one hundred trillion, one hundred twenty-two billion, three hundred ten million, twenty thousand, one hundred twenty-one".