100123000112021 has 8 divisors (see below), whose sum is σ = 100130921323224. Its totient is φ = 100115079229440.

The previous prime is 100123000111997. The next prime is 100123000112081. The reversal of 100123000112021 is 120211000321001.

It can be written as a sum of positive squares in 4 ways, for example, as 15343562731396 + 84779437380625 = 3917086^2 + 9207575^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 100123000112021 - 2³⁰ = 100121926370197 is a prime.

It is a super-3 number, since 3×100123000112021³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100123000111987 and 100123000112005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100123000112081) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1179082061 + ... + 1179166973.

It is an arithmetic number, because the mean of its divisors is an integer number (12516365165403).

Almost surely, 2^{100123000112021} is an apocalyptic number.

It is an amenable number.

100123000112021 is a deficient number, since it is larger than the sum of its proper divisors (7921211203).

100123000112021 is an equidigital number, since it uses as much as digits as its factorization.

100123000112021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 164311.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 100123000112021 its reverse (120211000321001), we get a palindrome (220334000433022).

The spelling of 100123000112021 in words is "one hundred trillion, one hundred twenty-three billion, one hundred twelve thousand, twenty-one".