Base | Representation |
---|---|
bin | 101110100111111001… |
… | …1000011110111111001 |
3 | 100120102202011001220111 |
4 | 1131033303003313321 |
5 | 3120022444024311 |
6 | 113555040024321 |
7 | 10143066511351 |
oct | 1351763036771 |
9 | 316382131814 |
10 | 100123033081 |
11 | 39509929735 |
12 | 174a30020a1 |
13 | 9598159096 |
14 | 4bbb529b61 |
15 | 290ee3dd21 |
hex | 174fcc3df9 |
100123033081 has 2 divisors, whose sum is σ = 100123033082. Its totient is φ = 100123033080.
The previous prime is 100123033063. The next prime is 100123033117. The reversal of 100123033081 is 180330321001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 67764419856 + 32358613225 = 260316^2 + 179885^2 .
It is a cyclic number.
It is not a de Polignac number, because 100123033081 - 27 = 100123032953 is a prime.
It is a super-4 number, since 4×1001230330814 (a number of 45 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (100123036081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50061516540 + 50061516541.
It is an arithmetic number, because the mean of its divisors is an integer number (50061516541).
Almost surely, 2100123033081 is an apocalyptic number.
It is an amenable number.
100123033081 is a deficient number, since it is larger than the sum of its proper divisors (1).
100123033081 is an equidigital number, since it uses as much as digits as its factorization.
100123033081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 100123033081 its reverse (180330321001), we get a palindrome (280453354082).
The spelling of 100123033081 in words is "one hundred billion, one hundred twenty-three million, thirty-three thousand, eighty-one".
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