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100130010143 = 711410281833
BaseRepresentation
bin101110101000000110…
…1101011010000011111
3100120110020021112122012
41131100031223100133
53120031240311033
6113555445341435
710143213020552
oct1352015532037
9316406245565
10100130010143
11395128646a9
12174a540787b
13959972ca17
144bbc424699
15291086b248
hex175036b41f

100130010143 has 4 divisors (see below), whose sum is σ = 101540292048. Its totient is φ = 98719728240.

The previous prime is 100130010107. The next prime is 100130010151. The reversal of 100130010143 is 341010031001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100130010143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100130018143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 705140846 + ... + 705140987.

It is an arithmetic number, because the mean of its divisors is an integer number (25385073012).

Almost surely, 2100130010143 is an apocalyptic number.

100130010143 is a deficient number, since it is larger than the sum of its proper divisors (1410281905).

100130010143 is an equidigital number, since it uses as much as digits as its factorization.

100130010143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1410281904.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 100130010143 its reverse (341010031001), we get a palindrome (441140041144).

The spelling of 100130010143 in words is "one hundred billion, one hundred thirty million, ten thousand, one hundred forty-three".

Divisors: 1 71 1410281833 100130010143