Base | Representation |
---|---|
bin | 101110101000000110… |
… | …1101011010000011110 |
3 | 100120110020021112122011 |
4 | 1131100031223100132 |
5 | 3120031240311032 |
6 | 113555445341434 |
7 | 10143213020551 |
oct | 1352015532036 |
9 | 316406245564 |
10 | 100130010142 |
11 | 395128646a8 |
12 | 174a540787a |
13 | 959972ca16 |
14 | 4bbc424698 |
15 | 291086b247 |
hex | 175036b41e |
100130010142 has 4 divisors (see below), whose sum is σ = 150195015216. Its totient is φ = 50065005070.
The previous prime is 100130010107. The next prime is 100130010151. The reversal of 100130010142 is 241010031001.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 241010031001 = 44351 ⋅5434151.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25032502534 + ... + 25032502537.
It is an arithmetic number, because the mean of its divisors is an integer number (37548753804).
Almost surely, 2100130010142 is an apocalyptic number.
100130010142 is a deficient number, since it is larger than the sum of its proper divisors (50065005074).
100130010142 is an equidigital number, since it uses as much as digits as its factorization.
100130010142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50065005073.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 100130010142 its reverse (241010031001), we get a palindrome (341140041143).
The spelling of 100130010142 in words is "one hundred billion, one hundred thirty million, ten thousand, one hundred forty-two".
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