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100130010142 = 250065005071
BaseRepresentation
bin101110101000000110…
…1101011010000011110
3100120110020021112122011
41131100031223100132
53120031240311032
6113555445341434
710143213020551
oct1352015532036
9316406245564
10100130010142
11395128646a8
12174a540787a
13959972ca16
144bbc424698
15291086b247
hex175036b41e

100130010142 has 4 divisors (see below), whose sum is σ = 150195015216. Its totient is φ = 50065005070.

The previous prime is 100130010107. The next prime is 100130010151. The reversal of 100130010142 is 241010031001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 241010031001 = 443515434151.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25032502534 + ... + 25032502537.

It is an arithmetic number, because the mean of its divisors is an integer number (37548753804).

Almost surely, 2100130010142 is an apocalyptic number.

100130010142 is a deficient number, since it is larger than the sum of its proper divisors (50065005074).

100130010142 is an equidigital number, since it uses as much as digits as its factorization.

100130010142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50065005073.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 100130010142 its reverse (241010031001), we get a palindrome (341140041143).

The spelling of 100130010142 in words is "one hundred billion, one hundred thirty million, ten thousand, one hundred forty-two".

Divisors: 1 2 50065005071 100130010142