100130201131 has 2 divisors, whose sum is σ = 100130201132. Its totient is φ = 100130201130.

The previous prime is 100130201099. The next prime is 100130201141. The reversal of 100130201131 is 131102031001.

It is a strong prime.

It is an emirp because it is prime and its reverse (131102031001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100130201131 - 2⁵ = 100130201099 is a prime.

It is a super-3 number, since 3×100130201131³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (100130201141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50065100565 + 50065100566.

It is an arithmetic number, because the mean of its divisors is an integer number (50065100566).

Almost surely, 2^100130201131 is an apocalyptic number.

100130201131 is a deficient number, since it is larger than the sum of its proper divisors (1).

100130201131 is an equidigital number, since it uses as much as digits as its factorization.

100130201131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 100130201131 its reverse (131102031001), we get a palindrome (231232232132).

The spelling of 100130201131 in words is "one hundred billion, one hundred thirty million, two hundred one thousand, one hundred thirty-one".