1001310303113 has 2 divisors, whose sum is σ = 1001310303114. Its totient is φ = 1001310303112.

The previous prime is 1001310303101. The next prime is 1001310303121. The reversal of 1001310303113 is 3113030131001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 981975956809 + 19334346304 = 990947^2 + 139048^2 .

It is a cyclic number.

It is not a de Polignac number, because 1001310303113 - 2¹⁴ = 1001310286729 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1001310303091 and 1001310303100.

It is not a weakly prime, because it can be changed into another prime (1001310303313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500655151556 + 500655151557.

It is an arithmetic number, because the mean of its divisors is an integer number (500655151557).

Almost surely, 2^{1001310303113} is an apocalyptic number.

It is an amenable number.

1001310303113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001310303113 is an equidigital number, since it uses as much as digits as its factorization.

1001310303113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 1001310303113 its reverse (3113030131001), we get a palindrome (4114340434114).

The spelling of 1001310303113 in words is "one trillion, one billion, three hundred ten million, three hundred three thousand, one hundred thirteen".