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100131337270049 is a prime number
BaseRepresentation
bin10110110001000110100100…
…110010011111001100100001
3111010112110111001120010112212
4112301012210302133030201
5101111022434320120144
6552543411252131505
730043151611415141
oct2661064462371441
9433473431503485
10100131337270049
11299a550951a068
12b29215a306b95
1343b44630a4817
141aa254db40921
15b899a4c3649e
hex5b11a4c9f321

100131337270049 has 2 divisors, whose sum is σ = 100131337270050. Its totient is φ = 100131337270048.

The previous prime is 100131337270007. The next prime is 100131337270057. The reversal of 100131337270049 is 940072733131001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 66404652699025 + 33726684571024 = 8148905^2 + 5807468^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100131337270049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100131337269988 and 100131337270015.

It is not a weakly prime, because it can be changed into another prime (100131337273049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50065668635024 + 50065668635025.

It is an arithmetic number, because the mean of its divisors is an integer number (50065668635025).

Almost surely, 2100131337270049 is an apocalyptic number.

It is an amenable number.

100131337270049 is a deficient number, since it is larger than the sum of its proper divisors (1).

100131337270049 is an equidigital number, since it uses as much as digits as its factorization.

100131337270049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 95256, while the sum is 41.

The spelling of 100131337270049 in words is "one hundred trillion, one hundred thirty-one billion, three hundred thirty-seven million, two hundred seventy thousand, forty-nine".