Base | Representation |
---|---|
bin | 10110110001000111011001… |
… | …000000010001110010110011 |
3 | 111010112112202002222002021112 |
4 | 112301013121000101302303 |
5 | 101111031233101103103 |
6 | 552544034224343535 |
7 | 30043212406512404 |
oct | 2661073100216263 |
9 | 433475662862245 |
10 | 100132213300403 |
11 | 299a5918a6a699 |
12 | b292363774bab |
13 | 43b4572727c8b |
14 | 1aa25d421b9ab |
15 | b89a06acacd8 |
hex | 5b11d9011cb3 |
100132213300403 has 2 divisors, whose sum is σ = 100132213300404. Its totient is φ = 100132213300402.
The previous prime is 100132213300381. The next prime is 100132213300417. The reversal of 100132213300403 is 304003312231001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100132213300403 - 230 = 100131139558579 is a prime.
It is not a weakly prime, because it can be changed into another prime (100132213300463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50066106650201 + 50066106650202.
It is an arithmetic number, because the mean of its divisors is an integer number (50066106650202).
Almost surely, 2100132213300403 is an apocalyptic number.
100132213300403 is a deficient number, since it is larger than the sum of its proper divisors (1).
100132213300403 is an equidigital number, since it uses as much as digits as its factorization.
100132213300403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 100132213300403 its reverse (304003312231001), we get a palindrome (404135525531404).
The spelling of 100132213300403 in words is "one hundred trillion, one hundred thirty-two billion, two hundred thirteen million, three hundred thousand, four hundred three".
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