100132320031333 has 4 divisors (see below), whose sum is σ = 101018446757388. Its totient is φ = 99246193305280.

The previous prime is 100132320031307. The next prime is 100132320031349. The reversal of 100132320031333 is 333130023231001.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1526665349889 + 98605654681444 = 1235583^2 + 9930038^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100132320031333 is a prime.

It is a super-2 number, since 2×100132320031333² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100132320031298 and 100132320031307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100132320031033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 443063362858 + ... + 443063363083.

It is an arithmetic number, because the mean of its divisors is an integer number (25254611689347).

Almost surely, 2^{100132320031333} is an apocalyptic number.

It is an amenable number.

100132320031333 is a deficient number, since it is larger than the sum of its proper divisors (886126726055).

100132320031333 is an equidigital number, since it uses as much as digits as its factorization.

100132320031333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 886126726054.

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 100132320031333 its reverse (333130023231001), we get a palindrome (433262343262334).

The spelling of 100132320031333 in words is "one hundred trillion, one hundred thirty-two billion, three hundred twenty million, thirty-one thousand, three hundred thirty-three".