Base | Representation |
---|---|
bin | 1001000110110110100001… |
… | …1101000000101000100011 |
3 | 1022110021010120102102220001 |
4 | 2101231220131000220203 |
5 | 2303024240211432321 |
6 | 33144020052400431 |
7 | 2052303301605445 |
oct | 221555035005043 |
9 | 38407116372801 |
10 | 10013321202211 |
11 | 3210697854448 |
12 | 1158795016117 |
13 | 578337c3c6b2 |
14 | 26890c3ca495 |
15 | 125709690c91 |
hex | 91b68740a23 |
10013321202211 has 2 divisors, whose sum is σ = 10013321202212. Its totient is φ = 10013321202210.
The previous prime is 10013321202197. The next prime is 10013321202263. The reversal of 10013321202211 is 11220212331001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10013321202211 - 25 = 10013321202179 is a prime.
It is a super-3 number, since 3×100133212022113 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (10013321202281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006660601105 + 5006660601106.
It is an arithmetic number, because the mean of its divisors is an integer number (5006660601106).
Almost surely, 210013321202211 is an apocalyptic number.
10013321202211 is a deficient number, since it is larger than the sum of its proper divisors (1).
10013321202211 is an equidigital number, since it uses as much as digits as its factorization.
10013321202211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 10013321202211 its reverse (11220212331001), we get a palindrome (21233533533212).
The spelling of 10013321202211 in words is "ten trillion, thirteen billion, three hundred twenty-one million, two hundred two thousand, two hundred eleven".
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