Base | Representation |
---|---|
bin | 101110101000001111… |
… | …0001010101011010011 |
3 | 100120110112102011200011 |
4 | 1131100132022223103 |
5 | 3120033342130024 |
6 | 114000122135351 |
7 | 10143264534211 |
oct | 1352036125323 |
9 | 316415364604 |
10 | 100134333139 |
11 | 39515247625 |
12 | 174a6951557 |
13 | 959a5b45c9 |
14 | 4bbcc2bcb1 |
15 | 2910e22094 |
hex | 175078aad3 |
100134333139 has 2 divisors, whose sum is σ = 100134333140. Its totient is φ = 100134333138.
The previous prime is 100134333107. The next prime is 100134333151. The reversal of 100134333139 is 931333431001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100134333139 - 25 = 100134333107 is a prime.
It is a super-3 number, since 3×1001343331393 (a number of 34 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 100134333139.
It is not a weakly prime, because it can be changed into another prime (100134331139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50067166569 + 50067166570.
It is an arithmetic number, because the mean of its divisors is an integer number (50067166570).
Almost surely, 2100134333139 is an apocalyptic number.
100134333139 is a deficient number, since it is larger than the sum of its proper divisors (1).
100134333139 is an equidigital number, since it uses as much as digits as its factorization.
100134333139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8748, while the sum is 31.
The spelling of 100134333139 in words is "one hundred billion, one hundred thirty-four million, three hundred thirty-three thousand, one hundred thirty-nine".
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