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10013498401 is a prime number
BaseRepresentation
bin10010101001101100…
…11101110000100001
3221211212011102110011
421110312131300201
5131001423422101
64333344004521
7503100221614
oct112466356041
927755142404
1010013498401
1142793a4615
121b35600741
13c377354aa
146adc7817b
153d9177751
hex254d9dc21

10013498401 has 2 divisors, whose sum is σ = 10013498402. Its totient is φ = 10013498400.

The previous prime is 10013498357. The next prime is 10013498413. The reversal of 10013498401 is 10489431001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6958062225 + 3055436176 = 83415^2 + 55276^2 .

It is a cyclic number.

It is not a de Polignac number, because 10013498401 - 27 = 10013498273 is a prime.

It is not a weakly prime, because it can be changed into another prime (10073498401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006749200 + 5006749201.

It is an arithmetic number, because the mean of its divisors is an integer number (5006749201).

Almost surely, 210013498401 is an apocalyptic number.

It is an amenable number.

10013498401 is a deficient number, since it is larger than the sum of its proper divisors (1).

10013498401 is an equidigital number, since it uses as much as digits as its factorization.

10013498401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 31.

The spelling of 10013498401 in words is "ten billion, thirteen million, four hundred ninety-eight thousand, four hundred one".