Base | Representation |
---|---|
bin | 10010101001101101… |
… | …01010011100000111 |
3 | 221211212021001200221 |
4 | 21110312222130013 |
5 | 131001432102333 |
6 | 4333345045211 |
7 | 503100526216 |
oct | 112466523407 |
9 | 27755231627 |
10 | 10013550343 |
11 | 427942a645 |
12 | 1b35626807 |
13 | c37753024 |
14 | 6adc8d07d |
15 | 3d9187d2d |
hex | 254daa707 |
10013550343 has 8 divisors (see below), whose sum is σ = 10506022016. Its totient is φ = 9531669600.
The previous prime is 10013550317. The next prime is 10013550377. The reversal of 10013550343 is 34305531001.
10013550343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10013550343 - 25 = 10013550311 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10013557343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2645796 + ... + 2649577.
It is an arithmetic number, because the mean of its divisors is an integer number (1313252752).
Almost surely, 210013550343 is an apocalyptic number.
10013550343 is a deficient number, since it is larger than the sum of its proper divisors (492471673).
10013550343 is an equidigital number, since it uses as much as digits as its factorization.
10013550343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5295465.
The product of its (nonzero) digits is 2700, while the sum is 25.
The spelling of 10013550343 in words is "ten billion, thirteen million, five hundred fifty thousand, three hundred forty-three".
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