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10014248753 is a prime number
BaseRepresentation
bin10010101001110010…
…10100111100110001
3221211220120112201222
421110321110330301
5131002121430003
64333412034425
7503106465335
oct112471247461
927756515658
1010014248753
114279867343
121b35902a15
13c37938ba2
146addd17c5
153d9274c38
hex254e54f31

10014248753 has 2 divisors, whose sum is σ = 10014248754. Its totient is φ = 10014248752.

The previous prime is 10014248743. The next prime is 10014248759. The reversal of 10014248753 is 35784241001.

10014248753 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9514636849 + 499611904 = 97543^2 + 22352^2 .

It is a cyclic number.

It is not a de Polignac number, because 10014248753 - 220 = 10013200177 is a prime.

It is not a weakly prime, because it can be changed into another prime (10014248759) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5007124376 + 5007124377.

It is an arithmetic number, because the mean of its divisors is an integer number (5007124377).

Almost surely, 210014248753 is an apocalyptic number.

It is an amenable number.

10014248753 is a deficient number, since it is larger than the sum of its proper divisors (1).

10014248753 is an equidigital number, since it uses as much as digits as its factorization.

10014248753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26880, while the sum is 35.

Adding to 10014248753 its reverse (35784241001), we get a palindrome (45798489754).

The spelling of 10014248753 in words is "ten billion, fourteen million, two hundred forty-eight thousand, seven hundred fifty-three".