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100142531511 = 3113034622167
BaseRepresentation
bin101110101000011110…
…1011100001110110111
3100120111002211200201120
41131100331130032313
53120042442002021
6114001013555023
710143424321161
oct1352075341667
9316432750646
10100142531511
1139519937140
12174a9645a73
13959c1c5109
144bbdd63931
1529119e12c6
hex1750f5c3b7

100142531511 has 8 divisors (see below), whose sum is σ = 145661864064. Its totient is φ = 60692443320.

The previous prime is 100142531501. The next prime is 100142531527. The reversal of 100142531511 is 115135241001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 100142531511 - 210 = 100142530487 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100142531501) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1517311051 + ... + 1517311116.

It is an arithmetic number, because the mean of its divisors is an integer number (18207733008).

Almost surely, 2100142531511 is an apocalyptic number.

100142531511 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

100142531511 is a deficient number, since it is larger than the sum of its proper divisors (45519332553).

100142531511 is a wasteful number, since it uses less digits than its factorization.

100142531511 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3034622181.

The product of its (nonzero) digits is 600, while the sum is 24.

Adding to 100142531511 its reverse (115135241001), we get a palindrome (215277772512).

The spelling of 100142531511 in words is "one hundred billion, one hundred forty-two million, five hundred thirty-one thousand, five hundred eleven".

Divisors: 1 3 11 33 3034622167 9103866501 33380843837 100142531511