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100144331141143 = 481720789771879
BaseRepresentation
bin10110110001010010101011…
…010010001011000000010111
3111010120201000121211011201211
4112301102223102023000113
5101111231042233004033
6552553400504002251
730044121611455222
oct2661225322130027
9433521017734654
10100144331141143
11299aaa77198803
12b294785a60387
1343b575410b943
141aa30237525b9
15b89eb58772cd
hex5b14ab48b017

100144331141143 has 4 divisors (see below), whose sum is σ = 100165120917840. Its totient is φ = 100123541364448.

The previous prime is 100144331141111. The next prime is 100144331141167. The reversal of 100144331141143 is 341141133441001.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100144331141143 - 25 = 100144331141111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100144331142143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10394881123 + ... + 10394890756.

It is an arithmetic number, because the mean of its divisors is an integer number (25041280229460).

Almost surely, 2100144331141143 is an apocalyptic number.

100144331141143 is a deficient number, since it is larger than the sum of its proper divisors (20789776697).

100144331141143 is an equidigital number, since it uses as much as digits as its factorization.

100144331141143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20789776696.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 100144331141143 its reverse (341141133441001), we get a palindrome (441285464582144).

The spelling of 100144331141143 in words is "one hundred trillion, one hundred forty-four billion, three hundred thirty-one million, one hundred forty-one thousand, one hundred forty-three".

Divisors: 1 4817 20789771879 100144331141143