Base | Representation |
---|---|
bin | 101110101000110011… |
… | …1011010101010101011 |
3 | 100120111212112201212122 |
4 | 1131101213122222223 |
5 | 3120103301111042 |
6 | 114002045501455 |
7 | 10143620000561 |
oct | 1352147325253 |
9 | 316455481778 |
10 | 100153535147 |
11 | 39525072356 |
12 | 174b127188b |
13 | 95a1578743 |
14 | 4bc15c9a31 |
15 | 29129667d2 |
hex | 17519daaab |
100153535147 has 2 divisors, whose sum is σ = 100153535148. Its totient is φ = 100153535146.
The previous prime is 100153535117. The next prime is 100153535171. The reversal of 100153535147 is 741535351001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100153535147 - 220 = 100152486571 is a prime.
It is not a weakly prime, because it can be changed into another prime (100153535117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50076767573 + 50076767574.
It is an arithmetic number, because the mean of its divisors is an integer number (50076767574).
Almost surely, 2100153535147 is an apocalyptic number.
100153535147 is a deficient number, since it is larger than the sum of its proper divisors (1).
100153535147 is an equidigital number, since it uses as much as digits as its factorization.
100153535147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31500, while the sum is 35.
Adding to 100153535147 its reverse (741535351001), we get a palindrome (841688886148).
The spelling of 100153535147 in words is "one hundred billion, one hundred fifty-three million, five hundred thirty-five thousand, one hundred forty-seven".
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