100200000011 has 4 divisors (see below), whose sum is σ = 101842623024. Its totient is φ = 98557377000.

The previous prime is 100200000001. The next prime is 100200000013. The reversal of 100200000011 is 110000002001.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 110000002001 = 17 ⋅6470588353.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100200000011 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100199999950 and 100200000004.

It is not an unprimeable number, because it can be changed into a prime (100200000013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 821311415 + ... + 821311536.

It is an arithmetic number, because the mean of its divisors is an integer number (25460655756).

Almost surely, 2^100200000011 is an apocalyptic number.

100200000011 is a deficient number, since it is larger than the sum of its proper divisors (1642623013).

100200000011 is an equidigital number, since it uses as much as digits as its factorization.

100200000011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1642623012.

The product of its (nonzero) digits is 2, while the sum is 5.

Adding to 100200000011 its reverse (110000002001), we get a palindrome (210200002012).

The spelling of 100200000011 in words is "one hundred billion, two hundred million, eleven", and thus it is an aban number.