Base | Representation |
---|---|
bin | 1001000111001111110100… |
… | …0110111111010010100001 |
3 | 1022110220122201010100211022 |
4 | 2101303331012333102201 |
5 | 2303132141202431032 |
6 | 33151101452255225 |
7 | 2052633446264006 |
oct | 221637506772241 |
9 | 38426581110738 |
10 | 10020110202017 |
11 | 3213560a92493 |
12 | 1159b6a771515 |
13 | 578b7a609446 |
14 | 268d93cdd8ad |
15 | 1259a56cb512 |
hex | 91cfd1bf4a1 |
10020110202017 has 2 divisors, whose sum is σ = 10020110202018. Its totient is φ = 10020110202016.
The previous prime is 10020110202007. The next prime is 10020110202023. The reversal of 10020110202017 is 71020201102001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5398229381281 + 4621880820736 = 2323409^2 + 2149856^2 .
It is a cyclic number.
It is not a de Polignac number, because 10020110202017 - 220 = 10020109153441 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10020110201986 and 10020110202004.
It is not a weakly prime, because it can be changed into another prime (10020110202007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5010055101008 + 5010055101009.
It is an arithmetic number, because the mean of its divisors is an integer number (5010055101009).
Almost surely, 210020110202017 is an apocalyptic number.
It is an amenable number.
10020110202017 is a deficient number, since it is larger than the sum of its proper divisors (1).
10020110202017 is an equidigital number, since it uses as much as digits as its factorization.
10020110202017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 10020110202017 its reverse (71020201102001), we get a palindrome (81040311304018).
The spelling of 10020110202017 in words is "ten trillion, twenty billion, one hundred ten million, two hundred two thousand, seventeen".
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