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10020110202017 is a prime number
BaseRepresentation
bin1001000111001111110100…
…0110111111010010100001
31022110220122201010100211022
42101303331012333102201
52303132141202431032
633151101452255225
72052633446264006
oct221637506772241
938426581110738
1010020110202017
113213560a92493
121159b6a771515
13578b7a609446
14268d93cdd8ad
151259a56cb512
hex91cfd1bf4a1

10020110202017 has 2 divisors, whose sum is σ = 10020110202018. Its totient is φ = 10020110202016.

The previous prime is 10020110202007. The next prime is 10020110202023. The reversal of 10020110202017 is 71020201102001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5398229381281 + 4621880820736 = 2323409^2 + 2149856^2 .

It is a cyclic number.

It is not a de Polignac number, because 10020110202017 - 220 = 10020109153441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10020110201986 and 10020110202004.

It is not a weakly prime, because it can be changed into another prime (10020110202007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5010055101008 + 5010055101009.

It is an arithmetic number, because the mean of its divisors is an integer number (5010055101009).

Almost surely, 210020110202017 is an apocalyptic number.

It is an amenable number.

10020110202017 is a deficient number, since it is larger than the sum of its proper divisors (1).

10020110202017 is an equidigital number, since it uses as much as digits as its factorization.

10020110202017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 17.

Adding to 10020110202017 its reverse (71020201102001), we get a palindrome (81040311304018).

The spelling of 10020110202017 in words is "ten trillion, twenty billion, one hundred ten million, two hundred two thousand, seventeen".